The tensile strength of the material is σ, the pressure is P, the outer diameter of the pipe D; the wall thickness of the pipe δ = (P * D) / (2 * σ / S) Where S is the safety factor; = 8; P less than 17.5MPa, S choose S = 6; P greater than 17.5MPa, S choose S = 4; we choose the safety factor of S = 6; 20 20 steel tensile strength of 410MPa, so the pipe can withstand the pressure P = (2 * σ / S * δ) / D = (2 * 410/6 * 3) / (10 + 6) = 26.25MPa> Set 17.5 so the safety factor to take S = 4 so the pipe can withstand the pressure P = (2 * σ / S * δ) / D = (2 * 410/4 * 3) / (10 + 6) = 39.375MPa The knowledge of the steel pipe
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